The distance between the two lines L_1 and L_2 given by L_1: x-1/2 = y-2/3 = -z-4/-6 and L_2: x-3/2 = y-3/3 = z+5/6 is Option 1: sqrt(293) Option 2: 12 Option 3: sqrt(293)7 Option 4: 13

The answer is 'sqrt(293)7'. View full solution:

CUET Mathematics - The distance between the two lines L_1 and L_2 given by L_1: x-1/2 = y-2/3 = -z-4/-6 and L_2: x-3/2 = y-3/3 = z+5/6 is | PYQs + Solutions

CUET Mathematics 2026 31st May Shift 2

Geometry

Hard

core

$\sqrt{293}$

$\dfrac{\sqrt{293}}{7}$

✅ Correct Option: 3

Related questions:

26th May Shift 2

Match the LIST-I with LIST-II

	LIST-I Equation of line		LIST-II Point on the line, direction ratios of the line
A.	$\dfrac{x-5}{3} = \dfrac{y-2}{2} = \dfrac{z+4}{-8}$	I.	$(-3, -2, 8), \langle 5, 2, -4 \rangle$
B.	$\dfrac{x+5}{3} = \dfrac{y+2}{2} = \dfrac{z-4}{-8}$	II.	$(3, 2, -8), \langle 5, 2, -4 \rangle$
C.	$\dfrac{x-3}{5} = \dfrac{y-2}{2} = \dfrac{z+8}{-4}$	III.	$(-5, -2, 4), \langle 3, 2, -8 \rangle$
D.	$\dfrac{x+3}{5} = \dfrac{y+2}{2} = \dfrac{z-8}{-4}$	IV.	$(5, 2, -4), \langle 3, 2, -8 \rangle$

Choose the correct answer from the options given below:

15 May Shift 1

Consider the lines $l_1: \frac{x-1}{0} = \frac{y-1}{1} = \frac{2-z}{1}$ and $l_2: \frac{x}{2} = \frac{y}{0} = \frac{2z-1}{4}$ , then which of the following are correct?

(A) Direction Ratio's of $l_1 = <0, 1, 1>$

(B) Direction Ratio's of $l_2 = <2, 0, 2>$

(D) Angle between $l_1$ and $l_2 =$ $\frac{2\pi}{3}$

Choose the correct answer from the options given below:

22 May Shift 2

Acute angle between the lines $\frac{x}{3} = \frac{y}{4} = \frac{z}{5}$ and $\frac{x-1}{4} = \frac{y+1}{-3} = \frac{z+10}{5}$ is:

CUET Mathematics 2026 31st May Shift 2 PYQs

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