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For what values of λ\lambda and μ\mu, the following system of linear equations:

x+y+2z=1,2x+y−z=4,x+2y+λz=μx+y+2z=1, 2x+y-z=4, x+2y+\lambda z=\mu

have infinitely many solution?

Solution

✅ Correct Option: 1

The coefficient determinant is 7−λ7-\lambda, which must vanish, so λ=7\lambda=7. Since the third coefficient row equals 3R1−R23R_1-R_2, consistency requires the same combination on the right: μ=3(1)−4=−1\mu=3(1)-4=-1.

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