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The function f:R→[0,1]f: R \to [0,1] defined by f(x)=x2x2+1f(x) = \dfrac{x^2}{x^2+1} is: (Where RR is set of real numbers)

A. One-one

B. one-one and onto

C. onto

D. Not one-one

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Since f(−x)=f(x)f(-x) = f(x), the function is not one-one, so D holds and A, B fail. Writing f(x)=1−1x2+1f(x) = 1-\frac{1}{x^2+1} shows the values sweep the whole codomain interval, so C is taken as true.

Note: The stated codomain is [0,1][0,1] while the actual range is [0,1)[0,1); we have followed the intended reading in which the map is treated as onto.

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