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If ∣a⃗∣=26,∣b⃗∣=7,∣a⃗×b⃗∣=35|\vec{a}| = \sqrt{26}, |\vec{b}| = 7, |\vec{a}\times\vec{b}| = 35 and θ\theta be the angle between a⃗\vec{a} and b⃗\vec{b} then

Match the LIST-I with LIST-II

LIST-ILIST-II
A.sin⁡θ\sin\thetaI.6161
B.cos⁡θ\cos\thetaII.5/265/\sqrt{26}
C.a⃗⋅b⃗\vec{a} \cdot \vec{b}III.1/261/\sqrt{26}
D.∣a⃗−b⃗∣2\vert \vec{a} - \vec{b} \vert^2IV.77

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

sin⁡θ=35726=526\sin\theta = \frac{35}{7\sqrt{26}} = \frac{5}{\sqrt{26}}, hence cos⁡θ=126\cos\theta = \frac{1}{\sqrt{26}} and a⃗⋅b⃗=26⋅7⋅126=7\vec{a}\cdot\vec{b} = \sqrt{26}\cdot7\cdot\frac{1}{\sqrt{26}} = 7. Then ∣a⃗−b⃗∣2=26+49−14=61|\vec{a}-\vec{b}|^2 = 26 + 49 - 14 = 61.

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