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The area enclosed between y2=4xy^2 = 4x, x=1x = 1 and x=4x = 4 in first quadrant is :

Solution

✅ Correct Option: 1

In the first quadrant y=2xy = 2\sqrt{x}. Area =∫142x dx=[43x3/2]14=43(8−1)=283= \int_1^4 2\sqrt{x}\,dx = \left[\frac{4}{3}x^{3/2}\right]_1^4 = \frac{4}{3}(8-1) = \frac{28}{3} square units.

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