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The ordinate of the point on the curve y2=8xy^2 = 8x for which abscissa and ordinate change at the same rate is:

Solution

✅ Correct Option: 3

Differentiating y2=8xy^2 = 8x with respect to time gives 2ydydt=8dxdt2y\frac{dy}{dt} = 8\frac{dx}{dt}. Setting dydt=dxdt\frac{dy}{dt} = \frac{dx}{dt} gives 2y=82y = 8, so y=4y = 4.

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