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The probability distribution table of a random variable X is given below.

XiX_iP(Xi)P(X_i)
01/8
1a
2b
31/8

If E(X)=32E(X) = \dfrac{3}{2}, then the values of a and b are:

Solution

✅ Correct Option: 1

Probabilities sum to 11, giving a+b=34a+b = \frac{3}{4}. From E(X)=a+2b+38=32E(X) = a+2b+\frac{3}{8} = \frac{3}{2} we get a+2b=98a+2b = \frac{9}{8}. Subtracting gives b=38b = \frac{3}{8} and hence a=38a = \frac{3}{8}.

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