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The rate of change in area of a triangle having sides 10cm and 12cm when the variable angle between them at an angle 60°60°, is:

Solution

✅ Correct Option: 1

Area A=12(10)(12)sin⁡θ=60sin⁡θA = \frac{1}{2}(10)(12)\sin\theta = 60\sin\theta, so dAdθ=60cos⁡θ\frac{dA}{d\theta} = 60\cos\theta. At θ=60∘\theta = 60^\circ this equals 60×12=3060 \times \frac{1}{2} = 30 cm2^2 per radian.

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