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The rate of change of x2−2\sqrt{x^2-2} with respect to xx+1\dfrac{x}{x+1} at x=2x=2 is :

Solution

✅ Correct Option: 3

With u=x2−2u = \sqrt{x^2-2} and v=xx+1v = \frac{x}{x+1}, the required rate is du/dxdv/dx\frac{du/dx}{dv/dx}. At x=2x=2, dudx=xx2−2=2\frac{du}{dx} = \frac{x}{\sqrt{x^2-2}} = \sqrt{2} and dvdx=1(x+1)2=19\frac{dv}{dx} = \frac{1}{(x+1)^2} = \frac{1}{9}, so the ratio is 929\sqrt{2}.

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