Skip to main contentSkip to solution

A LPP max Z=3x+8ymax\,Z = 3x + 8y subjected to the constraints 2x+y≤102x + y \le 10, x+3y≤15x + 3y \le 15, x,y≥0x,y \ge 0, then max Zmax\,Z is

Solution

✅ Correct Option: 1

Corner points are (0,0)(0,0), (5,0)(5,0), (0,5)(0,5) and the intersection of 2x+y=102x+y=10 with x+3y=15x+3y=15, namely (3,4)(3,4). Values of ZZ are 00, 1515, 4040 and 4141, so the maximum is 4141.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question