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Let f(x)f(x) be a function defined by f(x)=2x3−24x+107f(x) = 2x^3 - 24x + 107. If α\alpha and β\beta are the maximum and minimum values respectively in the interval [1,3][1,3], then α−β\alpha-\beta is equal to:

Solution

✅ Correct Option: 1

f′(x)=6x2−24=0f'(x) = 6x^2-24 = 0 gives x=2x = 2, which lies in [1,3][1,3]. Comparing f(1)=85f(1) = 85, f(2)=75f(2) = 75 and f(3)=89f(3) = 89, we get α=89\alpha = 89, β=75\beta = 75, so α−β=14\alpha-\beta = 14.

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