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If ∣1−252λ−1042λ∣=86\begin{vmatrix} 1 & -2 & 5 \\ 2 & \lambda & -1 \\ 0 & 4 & 2\lambda \end{vmatrix} = 86, the sum of the values of λ\lambda is:

Solution

✅ Correct Option: 2

Expanding along the first row gives (2λ2+4)+2(4λ)+5(8)=2λ2+8λ+44(2\lambda^2+4) + 2(4\lambda) + 5(8) = 2\lambda^2 + 8\lambda + 44. Setting this equal to 8686 gives λ2+4λ−21=0\lambda^2 + 4\lambda - 21 = 0, whose roots sum to −4-4.

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