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The function f(x)=2x3−3x2−36x+7f(x) = 2x^3 - 3x^2 - 36x + 7 is :

A. Increasing in (−∞,−2)(-\infty,-2)

B. Decreasing in (−2,3)(-2,3)

C. Neither increasing nor decreasing in (−2,3)(-2,3)

D. Increasing in (3,∞)(3,\infty)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

f′(x)=6x2−6x−36=6(x−3)(x+2)f'(x) = 6x^2 - 6x - 36 = 6(x-3)(x+2). This is positive on (−∞,−2)(-\infty,-2) and (3,∞)(3,\infty) and negative on (−2,3)(-2,3). So A, B and D are correct, while C is false since ff is strictly decreasing on (−2,3)(-2,3).

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