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CUET Mathematics 2026 31st May Shift 2 PYQs

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CUET Mathematics 2026 31st May Shift 2

Geometry

>

Hard

core

$x - \dfrac{\pi}{4}$

$\dfrac{\pi}{4} - x$

$\dfrac{9\pi}{4} - x$

$x - \dfrac{9\pi}{4}$

✅ Correct Option: 3

Related questions:

19th May Shift 2

Which one of the following is TRUE?

27 May Shift 1

Match List-I with List-II

List-I	List-II
(A) $\tan^{-1}\frac{2}{11} + \tan^{-1}\frac{7}{24}$	(I) $\frac{3\pi}{4}$
(B) $\tan^{-1}2 + \tan^{-1}3$	(II) $\pi$
(C) $\tan^{-1}1 + \tan^{-1}2 + \tan^{-1}3$	(III) $\tan^{-1}\frac{1}{2}$
(D) $\tan^{-1}\frac{1}{7} + \tan^{-1}\frac{1}{13}$	(IV) $\tan^{-1}\frac{2}{9}$

Choose the correct answer from the options given below:

29th May Shift 1

The value of $\tan^{-1}(\sqrt3)-\sec^{-1}(-2)$ is

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