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If A is a square matrix of order nn and kk is a scalar such that ∣kA∣=α∣A∣|kA| = \alpha|A| then the value of α\alpha is:

Solution

✅ Correct Option: 3

Multiplying a matrix by kk multiplies every one of its nn rows by kk, and each row contributes one factor of kk to the determinant. Hence ∣kA∣=kn∣A∣|kA| = k^n|A|, so α=kn\alpha = k^n.

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