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In a factory of fans, machine A, B and C manufacture respectively 20%, 40% and 40% of total fans. Out of their output 2, 3 and 5 percent are defective fans respectively. A fan is drawn at random from the products then the probability that the drawn fan is defective is:

Solution

✅ Correct Option: 2

By the law of total probability, P=0.2(0.02)+0.4(0.03)+0.4(0.05)=0.004+0.012+0.020=0.036P = 0.2(0.02) + 0.4(0.03) + 0.4(0.05) = 0.004 + 0.012 + 0.020 = 0.036.

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