If A is a non-singular matrix of order n, then adj(adj\ A) is equal to : Option 1: |A|^n-1 Option 2: |A|^n-2A Option 3: |A|^n-1A Option 4: |A|^(n-1)^2

The answer is '|A|^n-2A'. View full solution:

CUET Mathematics - If A is a non-singular matrix of order n, then adj(adj\ A) is equal to : | PYQs + Solutions

CUET Mathematics 2026 12th May Shift 2

Algebra

Medium

common

$|A|^{n-1}$

$|A|^{n-2}A$

$|A|^{n-1}A$

$|A|^{(n-1)^2}$

✅ Correct Option: 2

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Match List-I with List-II

List-I	List-II
(A) If $A=\begin{bmatrix}2 & -5\\3 & 4\end{bmatrix}$ , then adj A =	(I) $\begin{bmatrix}4 & -5\\-2 & -3\end{bmatrix}$
(B) If $A=\begin{bmatrix}2 & 3\\5 & -2\end{bmatrix}$ , then $A^{-1}=$	(II) $\begin{bmatrix}\frac{1}{17} & \frac{-5}{17}\\\frac{3}{17} & \frac{2}{17}\end{bmatrix}$
(C) If $A=\begin{bmatrix}-3 & 5\\2 & 4\end{bmatrix}$ , then adj A =	(III) $\begin{bmatrix}4 & 5\\-3 & 2\end{bmatrix}$
(D) If $A=\begin{bmatrix}2 & 5\\-3 & 1\end{bmatrix}$ , then $A^{-1}=$	(IV) $\begin{bmatrix}\frac{2}{19} & \frac{3}{19}\\\frac{5}{19} & \frac{-2}{19}\end{bmatrix}$

Choose the correct answer from the options given below: