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If AA is a non-singular matrix of order nn, then adj(adj A)adj(adj\ A) is equal to :

Solution

✅ Correct Option: 2

Using adj A=∣A∣A−1adj\,A=|A|A^{-1} twice, adj(adj A)=∣adj A∣(adj A)−1=∣A∣n−1⋅A∣A∣=∣A∣n−2Aadj(adj\,A)=|adj\,A|(adj\,A)^{-1}=|A|^{n-1}\cdot\dfrac{A}{|A|}=|A|^{n-2}A.

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