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If 2[345x]+[1y01]=[70105]2\begin{bmatrix}3 & 4 \\ 5 & x\end{bmatrix} + \begin{bmatrix}1 & y \\ 0 & 1\end{bmatrix} = \begin{bmatrix}7 & 0 \\ 10 & 5\end{bmatrix}, then the value of x−yx-y is :

Solution

✅ Correct Option: 3

From 2x+1=52x+1=5 we get x=2x=2. From 8+y=08+y=0 we get y=−8y=-8. So x−y=2−(−8)=10x-y=2-(-8)=10.

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