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Match List-I with List-II

List-IList-II
IntegralValue of the integral
(A) ∫12e2log⁡x dx\displaystyle\int_{1}^{2} e^{2\log x} \, dx(I) log⁡2\log 2
(B) ∫−11∣x∣ dx\displaystyle\int_{-1}^{1} \left\vert x \right\vert \, dx(II) 12\dfrac{1}{2}
(C) ∫01log⁡ex dx\displaystyle\int_{0}^{1} \log e^x \, dx(III) 73\dfrac{7}{3}
(D) ∫121x dx\displaystyle\int_{1}^{2} \dfrac{1}{x} \, dx(IV) 11

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

(A) e2log⁡x=x2e^{2\log x}=x^2, so ∫12x2dx=73\int_1^2 x^2dx = \frac{7}{3}.

(B) ∫−11∣x∣dx=2∫01x dx=1\int_{-1}^{1}|x|dx = 2\int_0^1 x\,dx = 1.

(C) log⁡ex=x\log e^x = x, so ∫01x dx=12\int_0^1 x\,dx = \frac{1}{2}.

(D) ∫121xdx=log⁡2\int_1^2\frac{1}{x}dx = \log 2.

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