CUET Mathematics - e^2x - e^-2xe^2x + e^-2xdx is equal to | PYQs + Solutions

CUET Mathematics 2025 2 June Shift 1

Calculus

Medium

common

$\frac{1}{2}\log_e|e^{2x} - e^{-2x}| + C$ , where $C$ is an arbitrary constant.

$\log_e|e^{2x} - e^{-2x}| + C$ , where $C$ is an arbitrary constant.

$\frac{1}{2}\log_e|e^{2x} + e^{-2x}| + C$ , where $C$ is an arbitrary constant.

$\log_e|e^{2x} + e^{-2x}| + C$ , where $C$ is an arbitrary constant.

✅ Correct Option: 3

CUET Mathematics 2025 2 June Shift 1 PYQs