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If A=[0a220b22c]A = \begin{bmatrix} 0 & a & 2 \\ -2 & 0 & b \\ -2 & 2 & c \end{bmatrix} is a skew symmetric matrix, then the value of (a+b+c)3(a + b + c)^3 is

Solution

Correct Option: 2

A matrix AA is skew-symmetric if AT=AA^T = -A.

This means:

  • All diagonal elements must be 0
  • Elements satisfy aij=ajia_{ij} = -a_{ji}

For the given matrix A=[0a220b22c]A = \begin{bmatrix} 0 & a & 2 \\ -2 & 0 & b \\ -2 & 2 & c \end{bmatrix}, the diagonal elements are 0,0,c0, 0, c.

Since all diagonal elements must be 0:

c=0c = 0


Comparing positions (1,2)(1,2) and (2,1)(2,1):

  • Position (1,2)=a(1,2) = a
  • Position (2,1)=2(2,1) = -2

Using the property a12=a21a_{12} = -a_{21}:

a=(2)a = -(-2)

a=2a = 2


Comparing positions (2,3)(2,3) and (3,2)(3,2):

  • Position (2,3)=b(2,3) = b
  • Position (3,2)=2(3,2) = 2

Using the property a23=a32a_{23} = -a_{32}:

b=(2)b = -(2)

b=2b = -2


The values are:

a=2a = 2

b=2b = -2

c=0c = 0

Therefore:

a+b+c=2+(2)+0a + b + c = 2 + (-2) + 0

a+b+c=0a + b + c = 0

(a+b+c)3=03(a + b + c)^3 = 0^3

(a+b+c)3=0(a + b + c)^3 = 0

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