Algebra

Probability

Medium

core

A bag contain 8 blue and 12 green balls. Two balls are drawn in succession without replacement. The probability that first is blue and second is green is

$\frac{42}{95}$

$\frac{71}{95}$

$\frac{8}{25}$

$\frac{24}{95}$

✅ Correct Option: 4

The bag contains 8 blue balls and 12 green balls, for a total of 20 balls. Two balls are drawn in succession without replacement.

For the first draw, there are 20 balls total and 8 are blue.

$P(\text{1st Blue}) = \frac{8}{20}$

After drawing one blue ball, 19 balls remain in the bag. The 12 green balls are still in the bag.

$P(\text{2nd Green | 1st Blue}) = \frac{12}{19}$

For both events to occur, multiply the probabilities:

$P(\text{Blue then Green}) = \frac{8}{20} \times \frac{12}{19}$

$= \frac{96}{380}$

$= \frac{24}{95}$

Therefore, the probability is $\frac{24}{95}$ .

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A bag contain 8 blue and 12 green balls. Two balls are drawn in succession without replacement. The probability that first is blue and second is green is

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