Skip to main contentSkip to solution

A man is known to speak the truth 3 out of 4 times. He throw a die and reports that it is five then the probability that it is actually five is

Solution

✅ Correct Option: 2

By Bayes' theorem, required probability =34⋅1634⋅16+14⋅56=1/81/8+5/24=38=\frac{\frac34\cdot\frac16}{\frac34\cdot\frac16+\frac14\cdot\frac56}=\frac{1/8}{1/8+5/24}=\frac{3}{8}. The numerator is truth about an actual five; the second term covers a lie when the outcome is not five.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question