10:[["$","title","0",{"children":"CUET Mathematics - _-10^10 |x| dx is equal to | PYQs + Solutions | AfterBoards"}],["$","meta","1",{"name":"description","content":"undefined The absolute value function |x| is defined as: - |x| = x when x \\>=q 0 - |x| = -x when x < 0

Since |x| behaves differently on either side of zero, the integral must be split at x = 0: _-10^10 |x| dx = _-10^0 |x| dx + _0^10 |x| dx

For x from -10 to 0: |x| = -x For x from 0 to 10: |x| = x Therefore: _-10^10 |x| dx = _-10^0 (-x) dx + _0^10 x dx

For the <=ft integral: _-10^0 (-x) dx = [-x^2/2]_-10^0 = -(0)^2/2 - (-(-10)^2/2) = 0 + 50 = 50

For the right integral: _0^10 x dx = [x^2/2]_0^10 = (10)^2/2 - 0 = 50

Adding both parts: _-10^10 |x| dx = 50 + 50 = 100 Therefore, _-10^10 |x| dx = 100"}],["$","link","2",{"rel":"manifest","href":"https://www.afterboards.in/manifest.json","crossOrigin":"$undefined"}],["$","meta","3",{"name":"keywords","content":"CUETMAT,MAT,Calculus,Integrals"}],["$","meta","4",{"name":"robots","content":"index, follow"}],["$","meta","5",{"name":"category","content":"education"}],["$","meta","6",{"name":"google-site-verification","content":"google"}],["$","meta","7",{"property":"og:title","content":"CUET Mathematics - _-10^10 |x| dx is equal to | PYQs + Solutions"}],["$","meta","8",{"property":"og:description","content":"undefined The absolute value function |x| is defined as: - |x| = x when x \\>=q 0 - |x| = -x when x < 0

Since |x| behaves differently on either side of zero, the integral must be split at x = 0: _-10^10 |x| dx = _-10^0 |x| dx + _0^10 |x| dx

For x from -10 to 0: |x| = -x For x from 0 to 10: |x| = x Therefore: _-10^10 |x| dx = _-10^0 (-x) dx + _0^10 x dx

For the <=ft integral: _-10^0 (-x) dx = [-x^2/2]_-10^0 = -(0)^2/2 - (-(-10)^2/2) = 0 + 50 = 50

For the right integral: _0^10 x dx = [x^2/2]_0^10 = (10)^2/2 - 0 = 50

Adding both parts: _-10^10 |x| dx = 50 + 50 = 100 Therefore, _-10^10 |x| dx = 100"}],["$","meta","9",{"property":"og:url","content":"https://www.afterboards.in/past-year-questions/cuet-mathematics/2025/slot-2/35"}],["$","meta","10",{"property":"og:site_name","content":"AfterBoards | CUET Mathematics Preparation"}],["$","meta","11",{"property":"og:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","meta","12",{"property":"og:type","content":"website"}],["$","meta","13",{"name":"twitter:card","content":"summary_large_image"}],["$","meta","14",{"name":"twitter:site","content":"afterboards.in"}],["$","meta","15",{"name":"twitter:title","content":"CUET Mathematics - _-10^10 |x| dx is equal to | PYQs + Solutions"}],["$","meta","16",{"name":"twitter:description","content":"undefined The absolute value function |x| is defined as: - |x| = x when x \\>=q 0 - |x| = -x when x < 0

Since |x| behaves differently on either side of zero, the integral must be split at x = 0: _-10^10 |x| dx = _-10^0 |x| dx + _0^10 |x| dx

For x from -10 to 0: |x| = -x For x from 0 to 10: |x| = x Therefore: _-10^10 |x| dx = _-10^0 (-x) dx + _0^10 x dx

For the <=ft integral: _-10^0 (-x) dx = [-x^2/2]_-10^0 = -(0)^2/2 - (-(-10)^2/2) = 0 + 50 = 50

For the right integral: _0^10 x dx = [x^2/2]_0^10 = (10)^2/2 - 0 = 50

Adding both parts: _-10^10 |x| dx = 50 + 50 = 100 Therefore, _-10^10 |x| dx = 100"}],["$","meta","17",{"name":"twitter:image","content":"https://www.afterboards.in/pyp/AfterBoards%20CUET%20Past%20Year%20Papers%20with%20Solutions.webp"}],["$","link","18",{"rel":"shortcut icon","href":"https://www.afterboards.in/favicon.ico","type":"image/x-icon","sizes":"48x48"}],"$L17","$L18","$L19","$L1a","$L1b","$L1c","$L1d","$L1e"]

CUET Mathematics 2025 13 May Shift 2 PYQs

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