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The slope of the tangent to the curve x=at2x = at^2, y=2aty = 2at at 't' is :

Solution

✅ Correct Option: 1

dxdt=2at\frac{dx}{dt} = 2at, dydt=2a\frac{dy}{dt} = 2a. So slope =dydx=2a2at=1t= \frac{dy}{dx} = \frac{2a}{2at} = \frac{1}{t}.

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