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If the mean of a binomial distribution is 12 and its standard deviation is 2, then the number of trials is :

Solution

✅ Correct Option: 1

Mean =np=12= np = 12 and variance =npq=4= npq = 4 (since SD =2= 2). So q=4/12=1/3q = 4/12 = 1/3, hence p=2/3p = 2/3. Then n=12/p=12×3/2=18n = 12/p = 12 \times 3/2 = 18.

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