Let X be a random variable. Let E (X) and Var (X) denote the mean and the variance of X respectively. Then match List-I with List-II | List-I | List-II | |---|---| | (A) If Var (X) = $a$, then Var (2X + 3) is | (I) 11$a$ | | (B) If E (X) = $a$, then E (2X) is | (II) 6$a$ | | (C) If Var (X) = $a$, then Var(3X - $a$) + Var ($\sqrt{2}x + \beta$) is | (III) 4$a$ | | (D) If E (X) = $\frac{5a}{12}$, then E (12X + $a$) is | (IV) 2$a$ | Choose the correct answer from the options given below:
(A) - (IV), (B) - (III), (C) - (I), (D) - (II)
(A) - (III), (B) - (IV), (C) - (II), (D) - (I)
(A) - (III), (B) - (IV), (C) - (I), (D) - (II)
(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

Question

Let X be a random variable. Let E (X) and Var (X) denote the mean and the variance of X respectively. Then match List-I with List-II | List-I | List-II | |---|---| | (A) If Var (X) = $a$, then Var (2X + 3) is | (I) 11$a$ | | (B) If E (X) = $a$, then E (2X) is | (II) 6$a$ | | (C) If Var (X) = $a$, then Var(3X - $a$) + Var ($\sqrt{2}x + \beta$) is | (III) 4$a$ | | (D) If E (X) = $\frac{5a}{12}$, then E (12X + $a$) is | (IV) 2$a$ | Choose the correct answer from the options given below:

(A) - (IV), (B) - (III), (C) - (I), (D) - (II)

(A) - (III), (B) - (IV), (C) - (II), (D) - (I)

(A) - (III), (B) - (IV), (C) - (I), (D) - (II)

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

Option 1: (A) - (IV), (B) - (III), (C) - (I), (D) - (II)

Option 2: (A) - (III), (B) - (IV), (C) - (II), (D) - (I)

Option 3: (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Option 4: (A) - (III), (B) - (I), (C) - (IV), (D) - (II)

AfterBoards · Accepted Answer

The answer is '(A) - (III), (B) - (IV), (C) - (I), (D) - (II)'. View full solution: