Skip to main contentSkip to solution

The slope of the tangent to the curve y=3x2+2kx−5y = 3x^2 + 2kx - 5 at x=1x=1 is 99. The value of kk is :

Solution

✅ Correct Option: 4

dydx=6x+2k\frac{dy}{dx} = 6x + 2k. At x=1x=1: 6+2k=96+2k=9, so 2k=32k=3, giving k=32k=\frac{3}{2}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question