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A pipe A can fill a tank in 4 hours. There are two outlet pipes, B and C, from the tank which can empty it in 8 and 10 hours respectively. If all the three pipes are opened simultaneously, how long will it take to fill the tank?

Solution

✅ Correct Option: 2

Pipe A fills the tank in 4 hours.

Pipe B empties the tank in 8 hours.

Pipe C empties the tank in 10 hours.

When all three pipes are opened simultaneously, Pipe A adds water while Pipes B and C drain water out.


Each pipe's rate of work per hour:

Pipe A fills 14\frac{1}{4} of the tank in 1 hour.

Pipe B empties 18\frac{1}{8} of the tank in 1 hour.

Pipe C empties 110\frac{1}{10} of the tank in 1 hour.


Net Rate = Filling Rate - Emptying Rate

Net Rate =14−18−110= \frac{1}{4} - \frac{1}{8} - \frac{1}{10}

The LCM of 4, 8, and 10 is 40.

14=1040\frac{1}{4} = \frac{10}{40}

18=540\frac{1}{8} = \frac{5}{40}

110=440\frac{1}{10} = \frac{4}{40}

Net Rate =1040−540−440= \frac{10}{40} - \frac{5}{40} - \frac{4}{40}

Net Rate =140= \frac{1}{40} of the tank per hour


If 140\frac{1}{40} of the tank is filled in 1 hour, then the full tank will be filled in:

Time =1÷140= 1 \div \frac{1}{40}

Time =40= 40 hours

Therefore, it will take 40 hours to fill the tank.

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