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The demand for a certain product is represented by the function p=300+25x−x2p = 300 + 25x - x^2 (in rupees), where x is the number of units demanded and p is the price per unit, then the marginal revenue when 15 units are sold, is

Solution

✅ Correct Option: 2

Marginal Revenue is the derivative of the Revenue function with respect to the number of units.

Given: p=300+25x−x2p = 300 + 25x - x^2

Revenue is given by:

R=p×xR = p \times x

R=(300+25x−x2)×xR = (300 + 25x - x^2) \times x

R=300x+25x2−x3R = 300x + 25x^2 - x^3


The Marginal Revenue is:

MR=dRdxMR = \dfrac{dR}{dx}

Taking the derivative:

MR=300+50x−3x2MR = 300 + 50x - 3x^2


For x=15x = 15 units:

MR=300+50(15)−3(15)2MR = 300 + 50(15) - 3(15)^2

MR=300+750−3(225)MR = 300 + 750 - 3(225)

MR=300+750−675MR = 300 + 750 - 675

MR=375MR = 375

Therefore, the marginal revenue when 15 units are sold is ₹375.

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