The interval in which the function f(x) = 2x^3 + 3x^2 - 12x + 1 is strictly increasing, is Option 1: (-∞, -2) (1, ∞) Option 2: (-∞, 1) Option 3: (-∞, -1) (2, ∞) Option 4: (-2, 1)

The answer is '(-∞, -2) (1, ∞)'. View full solution:

Calculus > Application of Derivatives

Medium

core

The interval in which the function $f(x) = 2x^3 + 3x^2 - 12x + 1$ is strictly increasing, is

$(-\infty, -2) \cup (1, \infty)$

$(-\infty, 1)$

$(-\infty, -1) \cup (2, \infty)$

$(-2, 1)$

✅ Correct Option: 1

Related questions:

2026: 30th May Shift 1

A balloon, which always remains spherical on inflation, is being inflated by pumping in 900 cubic centimeters of gas per second. The rate at which the radius of the balloon increases when the radius is 15 cm, is:

2025: 19 May Shift 1

The semi vertical angle of a right circular cone of maximum volume of a given slant height is

2026: 12th May Shift 2

A cylinder with height 'h' and radius of base is 'r' which is open at the top having a given outer surface area, then volume of the cylinder is maximum if

2026: 30th May Shift 1

Let $f(x) = (x-a)^2+(x-b)^2+(x-c)^2$ then $f(x)$ has a minimum value at $x =$

2025: 22 May Shift 2

The rate of change of the area of a circle with respect to its radius $r$ , when $r = 3$ cm, is:

2023: 22 May Shift 3

The equation of tangent to the curve $x = a \cos^3 t, y = a \sin^3 t$ at t is :

The interval in which the function $f(x) = 2x^3 + 3x^2 - 12x + 1$ is strictly increasing, is

Keyboard Shortcuts