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The least positive integer x satisfying 29≡x(mod5)29 \equiv x \pmod{5} is

Solution

✅ Correct Option: 3

The expression 29≡x(mod5)29 \equiv x \pmod{5} means 29 and xx leave the same remainder when divided by 5.


Dividing 29 by 5:

29=5×5+429 = 5 \times 5 + 4

The remainder is 4.


Since 29 leaves a remainder of 4 when divided by 5:

29≡4(mod5)29 \equiv 4 \pmod{5}

Therefore, the least positive integer x=4x = 4

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