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The mean of the number of heads in a simultaneous toss of three coins is

Solution

✅ Correct Option: 1

When tossing 3 coins simultaneously, all possible outcomes are:

OutcomeNumber of Heads
HHH3
HHT2
HTH2
THH2
HTT1
THT1
TTH1
TTT0

Total outcomes = 8 (all equally likely)


Counting the frequency of each result:

0 heads: 1 time (TTT)

1 head: 3 times (HTT, THT, TTH)

2 heads: 3 times (HHT, HTH, THH)

3 heads: 1 time (HHH)


Mean = (0×1)+(1×3)+(2×3)+(3×1)8\frac{(0 \times 1) + (1 \times 3) + (2 \times 3) + (3 \times 1)}{8}

Mean = 0+3+6+38\frac{0 + 3 + 6 + 3}{8}

Mean = 128\frac{12}{8}

Mean = 32\frac{3}{2}


Therefore, the mean of the number of heads in a simultaneous toss of three coins is 32\frac{3}{2}.

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