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If A and B are symmetric matrices of same order, then which of the following are correct?

(A) AB-BA is a skew-symmetric matrix.

(B) AB+BA is a skew-symmetric matrix.

(C) ABT−BATAB^T-BA^T is a skew-symmetric matrix.

(D) AB+BA is a symmetric matrix.

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 1

Given that A and B are symmetric matrices of the same order.

For symmetric matrices: AT=AA^T = A and BT=BB^T = B


Checking statement (A): AB - BA

(AB−BA)T=(AB)T−(BA)T(AB - BA)^T = (AB)^T - (BA)^T

=BTAT−ATBT= B^T A^T - A^T B^T

=BA−AB= BA - AB

=−(AB−BA)= -(AB - BA)

Therefore, AB - BA is skew-symmetric.


Checking statement (B): AB + BA

(AB+BA)T=(AB)T+(BA)T(AB + BA)^T = (AB)^T + (BA)^T

=BTAT+ATBT= B^T A^T + A^T B^T

=BA+AB= BA + AB

=AB+BA= AB + BA

Therefore, AB + BA is symmetric, not skew-symmetric.


Checking statement (C): ABT−BATAB^T - BA^T

Since B is symmetric: BT=BB^T = B

Since A is symmetric: AT=AA^T = A

ABT−BAT=AB−BAAB^T - BA^T = AB - BA

From statement (A), AB - BA is skew-symmetric.

Therefore, ABT−BATAB^T - BA^T is skew-symmetric.


Checking statement (D): AB + BA

From statement (B), (AB+BA)T=AB+BA(AB + BA)^T = AB + BA

Therefore, AB + BA is symmetric.


Statements (A), (C), and (D) are correct.

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