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If for the following data:

Year (x)2000200120022003200420052006
Production(in tonnes) (y)40454642475046

the equation of the straight line trend is y=45.143+1.036(x−2003)y = 45.143 + 1.036(x - 2003), then the trend value for the year 2004 is

Solution

✅ Correct Option: 1

The trend line equation is y=45.143+1.036(x−2003)y = 45.143 + 1.036(x - 2003) where yy represents production in tonnes and xx represents the year. The equation is centered around year 2003 as the base year.


For year 2004, substitute x=2004x = 2004 into the equation:

y=45.143+1.036(x−2003)y = 45.143 + 1.036(x - 2003)

y=45.143+1.036(2004−2003)y = 45.143 + 1.036(2004 - 2003)

y=45.143+1.036(1)y = 45.143 + 1.036(1)


y=45.143+1.036y = 45.143 + 1.036

y=46.179y = 46.179


Rounding to 2 decimal places gives y=46.18y = 46.18 tonnes.

Therefore, the trend value for the year 2004 is 46.18 tonnes.

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