CUET Mathematics - A integrating factor of the differential equation dy/dx + y/x = 1/x^2, (x > 0) is equal to | PYQs + Solutions

26 May Shift 2

Match List-I with List-II

List-I	List-II
Differential Equations	Order and degree
(A) $ydx + x\log(y/x)dy - 2xdy = 0$	(I) Order : 2, degree:1
(B) $\left(\frac{d^3y}{dx^3}\right)^2 + 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^2$	(II) Order :1, degree:1
(C) $\frac{dy}{dx} + \log\left(\frac{dy}{dx}\right) + x = y$	(III) Order : 3, degree:2
(D) $\left(\frac{ds}{dt}\right)^4 + 2s\frac{d^2s}{dt^2} = 0$	(IV) Order : 1, degree: Not defined

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22 May Shift 1

The solution of the differential equation $\frac{dy}{dx} - \frac{y}{x} = 2\log_e x$

30 May Shift 1

For the differential equation $y\frac{dx}{dx} - (x + 3y^2)dy = 0$ , which of the following statements are true?

(A) It is a linear differential equation

(B) It is a homogenous differential equation

(C) Its general solution is $x = 3y^2 + Cy$ : C is an arbitrary constant

(D) If $y(0) = 1$ , then its particular solution is $x = 3y^2 - 1$

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CUET Mathematics 2025 21 May Shift 1 PYQs