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If water is mixed with milk to gain 20% by selling the mixture at cost price. Then ratio of water to milk in mixture, is:

Solution

✅ Correct Option: 3

Let Cost Price of 1 liter of milk = ₹1\text{₹}1

Cost of water = ₹0\text{₹}0 (free)


Consider a mixture with:

Milk = MM liters

Water = WW liters

Actual cost = M×1+W×0M \times 1 + W \times 0

Actual cost = ₹M\text{₹}M


The mixture is sold at cost price of milk, meaning ₹1\text{₹}1 per liter.

Total mixture = (M+W)(M + W) liters

Selling price = (M+W)×1(M + W) \times 1

Selling price = ₹(M+W)\text{₹}(M + W)


Profit = Selling Price - Cost Price

Profit = (M+W)−M(M + W) - M

Profit = ₹W\text{₹}W


Given that profit percentage is 20%20\%:

Profit %=ProfitCost Price×100\text{Profit \%} = \dfrac{\text{Profit}}{\text{Cost Price}} \times 100

20=WM×10020 = \dfrac{W}{M} \times 100

20100=WM\dfrac{20}{100} = \dfrac{W}{M}

15=WM\dfrac{1}{5} = \dfrac{W}{M}


Therefore, the ratio of water to milk is:

W:M=1:5W : M = 1 : 5

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