Match List-I with List-II | List-I | List-II | | --- | --- | | Differential Equation | General solution | | --- | --- | | (A) dy/dx = y/x; x ≠ 0 | (I) y = cx; c is an arbitrary constant | | (B) x dx - y dy = 0; y ≠ 0, x ≠ 0 | (II) x^2 - y^2 = c; c is an arbitrary constant | | (C) (x^2 - 1)/y^2 + 1dx/dy = 1 | (III) 2x + 3y = c; c is an arbitrary constant | | (D) 2 dx + 3 dy = 0 | (IV) (x^3-y^3) = c + 3(x+y); c is an arbitrary constant | Choose the correct answer from the options given below:

Question

Option 1: (A) - (IV), (B) - (I), (C) - (II), (D) - (III)

Option 2: (A) - (II), (B) - (IV), (C) - (III), (D) - (I)

Option 3: (A) - (II), (B) - (IV), (C) - (I), (D) - (III)

Option 4: (A) - (I), (B) - (II), (C) - (IV), (D) - (III)

AfterBoards · Accepted Answer

The answer is '(A) - (I), (B) - (II), (C) - (IV), (D) - (III)'. View full solution:

List-I	List-II
Differential equation	Integrating factor
(A) $x\frac{dy}{dx} - y = 2x^2$	(I) $e^{-y}$
(B) $\frac{dy}{dx} + \frac{y}{x} = 2x$	(II) $\frac{1}{x}$
(C) $x\frac{dy}{dx} + 2y = x^2logx$	(III) $x$
(D) $\frac{dx}{dy} - x = y$	(IV) $x^2$

CUET Mathematics 2025 21 May Shift 1 PYQs

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