CUET Mathematics - The degree of the differential equation (2 + (dy/dx)^2)^3/2 = a^2 d^2y/dx^2 is: | PYQs + Solutions

CUET Mathematics 2025 16 May Shift 1

Calculus

Medium

common

✅ Correct Option: 4

Related questions:

19 May Shift 1

Match List-I with List-II

List-I	List-II
Differential Equation	Order and degree of differential equation
(A) $\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^2 = e^{\frac{dy}{dx}} + 1$	(I) Order = 1, Degree = 2
(B) $\left(\frac{d^2y}{dx^2}\right)^2 + 4\left(\frac{dy}{dx}\right)^3 = e^y - 1$	(II) Order = 2, Degree = 1
(C) $3\left(\frac{dy}{dx}\right) + 4y + e^y = \frac{dx}{dy}$	(III) Order = 2, Degree = 2
(D) $\frac{d^2y}{dx^2} + 3\left(\frac{dy}{dx}\right) = \left(e^y + \frac{dy}{dx}\right)^2$	(IV) Order = 2, Degree = Not defined

Choose the correct answer from the options given below:

13 May Shift 1

Let the degree and order of the differential equation $2x^3\frac{dy}{dx}-5\left(\frac{d^2y}{dx^2}\right)^2=6\left(\frac{dy}{dx}\right)^3$ be $m$ and $n$ respectively. Then

(A) m = 2

(B) n = 3

(D) mn = 4

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15 May Shift 1

Let $y(x) = a(x + 1) \log(x + 1) + bx + 5$ be the solution of the differential equation $x\frac{dy}{dx} = x + 1_{x}y(0) = 5$ , then the value of $(a + b)$ is:

CUET Mathematics 2025 16 May Shift 1 PYQs

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