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Pipe A can fill a tank three times faster than pipe B. If both pipes A and B are running together, they can fill the tank in 12 minutes, then the time taken by pipe B alone to fill the tank is:

Solution

Correct Option: 4

When pipe A fills the tank 3 times faster than pipe B, it means if pipe B takes some time to fill the tank, pipe A takes 1/3rd of that time.

Let pipe B alone take BB minutes to fill the tank.

Then pipe A alone takes B3\dfrac{B}{3} minutes to fill the tank.


If a pipe takes xx minutes to fill a tank, it fills 1x\dfrac{1}{x} of the tank per minute.

Pipe B's rate =1B= \dfrac{1}{B} tank per minute

Pipe A's rate =1B/3=3B= \dfrac{1}{B/3} = \dfrac{3}{B} tanks per minute


When both pipes run together, their rates add up:

Combined rate =3B+1B= \dfrac{3}{B} + \dfrac{1}{B}

Combined rate =4B= \dfrac{4}{B} tanks per minute


Both pipes together fill the tank in 12 minutes, so the combined rate =112= \dfrac{1}{12} tanks per minute.

4B=112\dfrac{4}{B} = \dfrac{1}{12}

4×12=B×14 \times 12 = B \times 1

B=48B = 48 minutes

Therefore, pipe B alone takes 48 minutes to fill the tank.

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