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Let the degree and order of the differential equation 2x3dydx−5(d2ydx2)2=6(dydx)32x^3\frac{dy}{dx}-5\left(\frac{d^2y}{dx^2}\right)^2=6\left(\frac{dy}{dx}\right)^3 be mm and nn respectively. Then

(A) m = 2

(B) n = 3

(C) m = 3

(D) mn = 4

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Order == the highest derivative in the equation.

Degree == the power of the highest derivative (equation must be polynomial in derivatives).


Given equation:

2x3dydx−5(d2ydx2)2=6(dydx)32x^3\frac{dy}{dx}-5\left(\frac{d^2y}{dx^2}\right)^2=6\left(\frac{dy}{dx}\right)^3


dydx\frac{dy}{dx} is the first derivative

d2ydx2\frac{d^2y}{dx^2} is the second derivative (highest)

Therefore, order m=2m = 2


The equation is already polynomial in derivatives. The highest order derivative is d2ydx2\frac{d^2y}{dx^2}, and it appears as:

(d2ydx2)2\left(\frac{d^2y}{dx^2}\right)^{2}

Therefore, degree n=2n = 2


(A)(A) m=2m = 2 ✓

(B)(B) n=3n = 3 ✗ (since n=2n = 2)

(C)(C) m=3m = 3 ✗ (since m=2m = 2)

(D)(D) mn=4mn = 4 ✓ (since m×n=2×2=4m \times n = 2 \times 2 = 4)


Options (A)(A) and (D)(D) are correct.

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