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Match List-I with List-II

List-IList-II
FunctionsIntegrals
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(A) ∫dxx2−4,x≠±2\int \frac{dx}{x^2 - 4}, x \neq \pm 2(I) log⁡∣x+4+x2∣+C\log \vert x + \sqrt{4 + x^2}\vert + C, where CC is an arbitrary constant
(B) ∫116−x2dx;∣x∣<4\int \frac{1}{\sqrt{16 - x^2}} dx; \vert x\vert < 4(II) sin⁡−1(x4)+C\sin^{-1} \left( \frac{x}{4} \right) + C, where CC is an arbitrary constant
(C) ∫116+x2dx\int \frac{1}{16 + x^2} dx(III) 14log⁡∣x−2x+2∣+C\frac{1}{4} \log \left\vert \frac{x-2}{x+2} \right\vert + C, where CC is an arbitrary constant
(D) ∫14+x2dx\int \frac{1}{\sqrt{4 + x^2}} dx(IV) 14tan⁡−1(x4)+C\frac{1}{4} \tan^{-1} \left( \frac{x}{4} \right) + C, where CC is an arbitrary constant

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

Each integral in List-I corresponds to a standard integral formula.

The relevant formulas are:

∫dxx2−a2=12alog⁡∣x−ax+a∣+C\int \frac{dx}{x^2 - a^2} = \frac{1}{2a} \log \left|\frac{x-a}{x+a}\right| + C

∫dxa2−x2=sin⁡−1(xa)+C\int \frac{dx}{\sqrt{a^2 - x^2}} = \sin^{-1}\left(\frac{x}{a}\right) + C

∫dxa2+x2=1atan⁡−1(xa)+C\int \frac{dx}{a^2 + x^2} = \frac{1}{a} \tan^{-1}\left(\frac{x}{a}\right) + C

∫dxx2+a2=log⁡∣x+x2+a2∣+C\int \frac{dx}{\sqrt{x^2 + a^2}} = \log \left|x + \sqrt{x^2 + a^2}\right| + C


(A) ∫dxx2−4\int \frac{dx}{x^2 - 4}, where a=2a = 2:

=12(2)log⁡∣x−2x+2∣+C= \frac{1}{2(2)} \log \left|\frac{x-2}{x+2}\right| + C

=14log⁡∣x−2x+2∣+C= \frac{1}{4} \log \left|\frac{x-2}{x+2}\right| + C

(A)→(III)(A) \rightarrow (III)


(B) ∫dx16−x2\int \frac{dx}{\sqrt{16 - x^2}}, where a=4a = 4:

=sin⁡−1(x4)+C= \sin^{-1}\left(\frac{x}{4}\right) + C

(B)→(II)(B) \rightarrow (II)


(C) ∫dx16+x2\int \frac{dx}{16 + x^2}, where a=4a = 4:

=14tan⁡−1(x4)+C= \frac{1}{4} \tan^{-1}\left(\frac{x}{4}\right) + C

(C)→(IV)(C) \rightarrow (IV)


(D) ∫dx4+x2\int \frac{dx}{\sqrt{4 + x^2}}, where a=2a = 2:

=log⁡∣x+x2+4∣+C= \log \left|x + \sqrt{x^2 + 4}\right| + C

(D)→(I)(D) \rightarrow (I)


(A)→(III)(A) \rightarrow (III)

(B)→(II)(B) \rightarrow (II)

(C)→(IV)(C) \rightarrow (IV)

(D)→(I)(D) \rightarrow (I)

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