CUET Mathematics 2025 16 May Shift 1 PYQs

The value of the definite integral $I = \int_0^2 x\sqrt{2-x} dx$ is:

$\int_{1}^{2} \frac{\sqrt{x}}{\sqrt{3 - x} + \sqrt{x}} dx$ is equal to

$\int_1^{\sqrt{3}} \frac{1}{1+x^2} dx$ is equal to: