The degree of the differential equation (1-(d y/d x)^2)^3/2=k d^2 yd x^2 is : Option 1: 1 Option 2: 2 Option 3: 3 Option 4: 3/2

The answer is '2'. View full solution:

Calculus > Differential Equations

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The degree of the differential equation $\left(1-\left(\frac{d y}{d x}\right)^{2}\right)^{\frac{3}{2}}=k \frac{d^{2} y}{d x^{2}}$ is :

$1$

$2$

$3$

$\frac{3}{2}$

✅ Correct Option: 2

Related questions:

2025: 29 May Shift 2

Match List-I with List-II:

List-I	List-II
Differential Equations	Degree/Order
(A) Degree of the differential equation $\frac{d^3y}{dx^3} + 2 \log x.y = 0$	(I) 3
(B) Order of the differential equation $\frac{d^4y}{dx^4} + \left(\frac{dy}{dx}\right)^4 + xy = 0$	(II) 2
(C) Degree of the differential equation $\left(\frac{d^4y}{dx^4}\right)^2 + \left(\frac{dy}{dx}\right)^3 + x^2y = 0$	(III) 1
(D) Order of the differential equation $\frac{d^3y}{dx^3} + y\left(\frac{dy}{dx}\right)^3 = 0$	(IV) 4

2026: 22nd May Shift 2

The product of the order and degree of the differential equation $\left(\frac{d^3y}{dx^3}\right)^2 - 3\frac{d^2y}{dx^2} + 2\left(\frac{dy}{dx}\right)^4 = y^4$ is

2026: 26th May Shift 2

General solution of the differential equation $(1+x^2)dy + 2xy\,dx = \cot x\,dx$ is:

(where $C$ is an arbitrary constant)

2023: 30 May Shift 3

Solution of differential equation $x dy - y dx = 0$ respresents :

2023: 23 May Shift 3

In the context of differential equation

Match List I with List II

LIST I	LIST II
A. $\frac{dy}{dx} = \frac{1+y^2}{1+x^2}$	I. Not a differential equation
B. $x^2 \frac{dy}{dx} = x^2 - 2y^2 + xy$	II. Linear first order
C. $\sin x + y = \cos(x+y)$	III. Variable separable
D. $(x+y)\frac{dy}{dx} = 1$	IV. Homogenous

Choose the correct answer from the options given below:

2023: 30 May Shift 3

The degree of the differential equation $\left[1 + \left(\frac{dy}{dx}\right)\right]^3 = \left(\frac{d^2 y}{dx^2}\right)^2$ is :

The degree of the differential equation $\left(1-\left(\frac{d y}{d x}\right)^{2}\right)^{\frac{3}{2}}=k \frac{d^{2} y}{d x^{2}}$ is :

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