The area (sq.units) bounded by the curve y = sinx, π ≤ x ≤ 2π and the x-axis is

The curve $y = \sin x$ for $\pi \leq x \leq 2\pi$ lies below the x-axis.

At $x = \pi$: $\sin(\pi) = 0$

At $x = \frac{3\pi}{2}$: $\sin(\frac{3\pi}{2}) = -1$

At $x = 2\pi$: $\sin(2\pi) = 0$

---

Since the curve is below the x-axis, $|\sin x| = -\sin x$ in this interval.

Area $= \int_{\pi}^{2\pi} |\sin x| \, dx$

Area $= \int_{\pi}^{2\pi} (-\sin x) \, dx$

---

The integral of $-\sin x$ is $\cos x$.

$\int (-\sin x) \, dx = \cos x$

Applying limits from $\pi$ to $2\pi$:

Area $= [\cos x]_{\pi}^{2\pi}$

Area $= \cos(2\pi) - \cos(\pi)$

Area $= 1 - (-1)$

Area $= 2$

---

Therefore, the area bounded by the curve $y = \sin x$ and the x-axis for $\pi \leq x \leq 2\pi$ is $2$ square units.