For a Poisson distribution where P[X=k]=P[X=k+1], the mean value of X needs to be determined.
The probability formula for a Poisson distribution is:
P[X=n]=n!λn×e−λ
where λ is the mean of the distribution.
Given that P[X=k]=P[X=k+1]:
P[X=k]=k!λk×e−λ
P[X=k+1]=(k+1)!λk+1×e−λ
Setting them equal:
k!λk×e−λ=(k+1)!λk+1×e−λ
Canceling e−λ from both sides:
k!λk=(k+1)!λk+1
Since (k+1)!=(k+1)×k!:
k!λk=(k+1)×k!λk+1
Canceling k!:
λk=k+1λk+1
(k+1)×λk=λk+1
(k+1)×λk=λ×λk
Dividing both sides by λk:
k+1=λ
Therefore, the mean value λ=k+1