(x-3)e^x/(x-1)^3 dx is equal to Option 1: e^x/(x-1) + C, C is an arbitary constant Option 2: e^x/(x-3)^2 + C, C is an arbitary constant Option 3: e^x/(x-1)^2 + C, C is an arbitary constant Option 4: e^x/(x-1)^3 + C, C is an arbitary constant

The answer is 'e^x/(x-1)^2 + C, C is an arbitary constant'. View full solution:

Calculus > Integrals

Medium

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$\int \frac{(x-3)e^x}{(x-1)^3} dx$ is equal to

$\frac{e^x}{(x-1)} + C$ , C is an arbitary constant

$\frac{e^x}{(x-3)^2} + C$ , C is an arbitary constant

$\frac{e^x}{(x-1)^2} + C$ , C is an arbitary constant

$\frac{e^x}{(x-1)^3} + C$ , C is an arbitary constant

✅ Correct Option: 3

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