CUET Mathematics - Match **List-I** with **List-II** | List-I | List-II | |---|---| | Differential equation | Integrating factor | | (A) dx/dy+2x/y=y^2 | (I) e^x | | (B) dy/dx+y=e^-x | (II) 1sqrt(y) | | (C) dy/dx-y/2=x | (III) y^2 | | (D) dx/dy-1/2x/y= y | (IV) e^-x/2 | Choose the correct answer from the options given below: | PYQs + Solutions

CUET Mathematics 2026 30th May Shift 2

Calculus

Medium

core

(A) - (III), (B) - (I), (C) - (IV), (D) - (II)

(A) - (III), (B) - (I), (C) - (II), (D) - (IV)

(A) - (III), (B) - (II), (C) - (I), (D) - (IV)

(A) - (I), (B) - (IV), (C) - (III), (D) - (II)

✅ Correct Option: 1

Related questions:

14 May Shift 2

The general solution of the differential equation $\frac{dy}{dx} = e^{x-y} + x^2e^{-y}$ is equal to:

30th May Shift 1

Match the LIST-I with LIST-II

	LIST-I Differential equation		LIST-II Sum of the order and the degree of the differential equation
A.	$\dfrac{d}{dx}\left(\dfrac{dy}{dx}\right) = 1$	I.	$2$
B.	$4 + \left(\dfrac{dy}{dx}\right)^4 = 7\left(\dfrac{d^2y}{dx^2}\right)^3$	II.	$3$
C.	$x^3\left(\dfrac{d^2y}{dx^2}\right)^2 + x\left(\dfrac{dy}{dx}\right)^4 + 1 = 0$	III.	$5$
D.	$\dfrac{dy}{dx} = x^4 e^{-3y}$	IV.	$4$

Choose the correct answer from the options given below:

2 June Shift 1

The solution of the differential equation $ydx + (x - y^2)dy = 0$ is

CUET Mathematics 2026 30th May Shift 2 PYQs