CUET Mathematics - If y = ((x + sqrt(x^2+a^2)))^1 and x ≠ 1-a^2/2, then (x^2+a^2)d^2y/dx^2 + xdy/dx is equal to: | PYQs + Solutions

CUET Mathematics 2025 16 May Shift 1

Calculus

Medium

applied

✅ Correct Option: 3

Related questions:

3 June Shift 1

If $y = \log_e(\sec e^{x^2})$ then $\frac{dy}{dx} =$

14 May Shift 2

Match List-I with List-II

List-I	List-II
Function	Derivative
(A) $y = \sin^{-1} x + \sin^{-1} \sqrt{1 - x^2}; \|x\| < 1$	(I) $\frac{dy}{dx} = \frac{1}{2y-1}$
(B) $y = \sqrt{x + y}, x+y > 0 \text{ and } y \neq \frac{1}{2}$	(II) $\frac{dy}{dx} = 10^x \log_e 10$
(C) $y = \log_{10} x, x > 0$	(III) $\frac{dy}{dx} = 0$
(D) $y = 10^x$	(IV) $\frac{dy}{dx} = \frac{1}{x \log_e 10}$

Choose the correct answer from the options given below:

30 May Shift 2

If $y = 3e^{2x} + 2e^{3x}$ , then $\frac{d^2y}{dx^2} + 6y$ is equal to

CUET Mathematics 2025 16 May Shift 1 PYQs