CUET Mathematics - If a is a non-zero vector, then always | PYQs + Solutions

CUET Mathematics 2025 16 May Shift 1

Algebra

Easy

core

$\vec{a}.\vec{a} = 0$

$\vec{a}.\vec{a} > 0$

$\vec{a}.\vec{a} < 0$

$\vec{a}.\vec{a} = 1$

✅ Correct Option: 2

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Match List-I with List-II

List-I	List-II
(A) The vectors $\vec{a}$ = $\hat{i} + \hat{j} + 2\hat{k}$ and $\vec{i} + \lambda\hat{j} + \hat{k}$ are perpendicular if λ is equal to	(I) 1
(B) The vectors $3\hat{i} + q\hat{j} - \hat{k}$ and $2\hat{i} + \hat{j} - \hat{k}$ are collinear if λ is equal to	(II) -1
(C) The number of vectors of unit-length which are perpendicular to both the vectors $\vec{a}$ = $\hat{i} + \hat{j} + 2\hat{k}$ and $\vec{b}$ = $3\hat{i} - \hat{j} + \hat{k}$ is	(III) 2/3
(D) If $\\|\vec{a}\\|$ = 1 and $\vec{a}\cdot\vec{b}$ = 0, then $\\|\vec{a}\\|$ is equal to	(IV) 2

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CUET Mathematics 2025 16 May Shift 1 PYQs

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